jquery on live(click) submit form

what I want to do, this I have a drop down box that lets my admin users rate pictures G rated and X rated. once they have selected this option I would like the form to be submitted.

I thought it would be as easy as sending the form ID, but seems not.

this is the only thing 开发者_如何转开发the user needs to do in the form.

the html form looks like this

<form id="photo1">
<input id="1" name="pictureid" hidden /> 
<select name="phototype">
 <option value="G">G Rated</option>
 <option value="X">X Rated</option>
</select>
</form>

If you want to submit the form when the onchange event is fired, this is the code:

$('#photo1 select').change(function () {
        $("#photo1").submit();
    });

$('#photo1 select').change(function() {
    $('#photo1').submit();

    return true;
});

This should be enough

$('select[name="phototype"]').change(function(){
  this.form.submit();
});

It finds the relative form automatically, so it can apply to multiple forms as well.

Or if you want this with .live() due to loading forms dynamically, then use

$('select[name="phototype"]').live('change',function(){
  this.form.submit();
});

The problem with your code currently is that your user can't select "G-rated", because it's selected by default. You should add a blank option. You probably also need a value for your hidden element:

<form id="photo1">
    <input id="1" name="pictureid" value="1" hidden /> 
    <select name="phototype" id="phototype">
        <option value=""></option>
        <option value="G">G Rated</option>
        <option value="X">X Rated</option>
    </select>
</form>

You could then use the following jQuery:

$('#phototype').change(function() {
    if (this.value) {
        $(this).closest('form').submit();
    }
});

jsFiddle

working demo

$('select').change(function(){
    $(this).closest('form').submit();   
});

$('select').live('change',function(){
    $(this).closest('form').submit();   
});