Haskell list comprehension for finding primes
I'm trying to find all the primes less than some integer n
as concisely as possible, using list comprehensions. I'm learning Haskell, and this is just an exercise. I'd like to write something like:
isqrt :: Integral a => a -> a
isqrt = floor . sqrt . fromIntegral
primes :: Integral a => a -> [a]
primes n = [i | i <- [1,3..n], mod i k /= 0 | k <- primes (isqrt i)]
which of course doesn't work. Is there a way to have a list comprehension inside a list comprehension?
Here is the error I'm getting:
exercise-99-1.hs:138:39: N开发者_JAVA技巧ot in scope: `k'
exercise-99-1.hs:138:46:
Illegal parallel list comprehension: use -XParallelListComp
exercise-99-1.hs:138:68: Not in scope: `i'
BUT - I wasn't really expecting the syntax to even be legit :-)
The intent was to translate as directly as possible: " primes n
= the set of odd integers i
less than n
such that i
is not divisible by any k
, for all k
in the set: primes (isqrt i)
" - more or less. (I hope I got that right?)
Thanks!
I made some progress with the following:
primes :: Integral a => a -> [a]
primes 2 = [2]
primes n = 2:[i | i <- [3,5..n], all (\k -> if (mod i k /= 0) then True else False)
(primes (isqrt i))]
Is there a shorter way to write the lambda predicate?
edit: Yes, there is, thanks to the remarks in the comments!
primes :: Integral a => a -> [a]
primes 2 = [2]
primes n = 2:[i | i <- [3,5..n], all ((/= 0) . mod i) (primes (isqrt i))]
your code,
primes n = [i | i <- [1,3..n], mod i k /= 0
| k <- primes (isqrt i)]
is interpreted as parallel list comprehension; i.e. instead of combining the two generators in the usual nested fashion, they are combined in parallel:
primes n = [i | (i,k) <- zip [i | i <- [1,3..n], mod i k /= 0]
-- not in scope: k ^
[k | k <- primes (isqrt i)] ]
-- not in scope: i ^
Instead, to express what you intended, it can be written as
primes 1 = []
primes n = 2:[i | i <- [3,5..n], and [mod i k /= 0 | k <- primes (isqrt i)]]
thus having a list comprehension inside a list comprehension - but as part of a guard, not generator. The function and :: [Bool] -> Bool
makes this possible.
Incidentally, calling primes
recursively for each new candidate i
makes it run slow, with run times growing too fast, empirically:
> length $ primes 10000 -- => 1229 (0.50 secs)
> length $ primes 20000 -- => 2262 (1.40 secs)
> logBase (2262/1229) (1.4/0.5) -- => 1.6878 ~ n^1.69
> length $ primes 40000 -- => 4203 (4.07 secs)
> logBase (4203/2262) (4.07/1.4) -- => 1.7225 ~ n^1.72
Optimal trial division usually runs at ~ n1.4..1.45, list-based sieve of Eratosthenes at ~ n1.2..1.25 and, if optimally implemented on mutable arrays, at ~ n1.0..1.1 (with n the number of primes produced, not the upper limit).
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