Order SQL records with same value by second criteria

I order some records by their value. If two records have the same value i want to order those two records by their date. For example:

record1 34 1.1.2000
record2 26 3.4.2000
record3 26 2.4.2001开发者_如何学Python
record4 76 1.5.2000

This should be ordered like this:

record4 76 1.5.2000
record1 34 1.5.2000
record3 26 2.4.2001
record2 26 3.4.2000

How can i manage this in SQL?

Like this:

SELECT * 
FROM myTable
ORDER BY Value, Date

Each of these can also have an ASC/DESC specifier:

SELECT * 
FROM myTable
ORDER BY Value ASC, Date DESC

Here is a link to MSDN, describing the syntax of the ORDER BY clause.

SELECT * FROM records ORDER BY field1, field2

Just add the second order by column to the ORDER BY clause:

SELECT field1, field2, field3
FROM table
ORDER BY value, date