How to return folders that do not contain a certain file?
I'd like to filter out folders that do not contain poster.* (JPG/PNG/GIF) OR folder.* (JPG/PNG/开发者_Go百科GIF). I created the following code but I'm a bit clueless on how to do this efficiently:
<?php
$dir = "/share/test/";
if ($handle = opendir($dir)) {
while (false !== ($file = readdir($handle))) {
if ($file != "." &&
$file != ".." &&
$file != ".DS_Store" &&
$file != "_Incoming" &&
is_dir($dir.$file) &&
!file_exists($dir.$file."/poster.*") ){
echo "$file\n";
}
}
closedir($handle);
}
?>
Thanks!
here ya go, hope it helps:
<?php
/**
* Recursive function that will check all folders in the
* requested directory for keywords [$lookfor] [Any extention]
* true,false on returning notfounds
*
* @param $path to folder
* @param $lookfor word in filename or folder
* @param $showNotfounds [true|false]
* @return echo'ed out
*/
function lookfor($path,$lookfor,$showNotfounds=false){
if(file_exists($path) && is_readable($path)){}else{die('Error reading folder ./'.$path.'');}
if ($handle = @opendir($path)) {
while ($file = readdir($handle)){
if ($file=='.' || $file=='..'){}else{
if (is_dir($path."/".$file)){
//Recursive
if(stristr($file, $lookfor) === FALSE) {
//[folder]missing
echo ($showNotfounds==true) ? '<font color="red"><b>'.$path.'/'.$file.'</b></font>: Not a '.$lookfor.'<br/>': '';
}else{
//[folder]exists
echo '<font color="green"><b>'.$path.'/'.$file.'</b></font>: Is a '.$lookfor.'<br/>';
}
lookfor($path."/".$file,$lookfor,$showNotfounds);
}else{
if(stristr($file, $lookfor) === FALSE) {
//[file]missing
echo ($showNotfounds==true) ? '<font color="red"><b>'.$path.'/'.$file.'</b></font>: Not a '.$lookfor.'<br/>': '';
}else{
//[file]exists
echo '<font color="green"><b>'.$path.'/'.$file.'</b></font>: Is a '.$lookfor.'<br/>';
}
}
}
}
closedir($handle);
}
}
//example usage
lookfor('.','folder.',true);
echo '<hr>';
lookfor('.','poster.',true);
echo '<hr>';
lookfor('.','poster.jpg',false);
?>
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