How to echo a set of variables with on a new line?

How to print set of variables in one line and next set in new line?

Example:

echo $uname $uid $fullname $homedirectory
开发者_JAVA百科

as

bob 1 bobby /sbin
max 2 maxwell /bin

I tried using \n at the end but it is giving new line for every variable like this

bob
1
bobby
/sbin
max
2
maxwell
/bin

But how to have \n at the end of set of variables?

Using echo with -e does what you are looking for

$ echo -e $HOME'\n'$HOME'\n'$HOME
/home/user
/home/user
/home/user

A simple man echo is your friend

echo $uname $uid $fullname $homedirectory;echo

by just calling another echo w/o an argument, it will print a new line at the end of the previously printed line with the variables.

I don't see a reason you couldn't just use,

printf  "$uname $uid $fullname $homedirectory\n"

instead, which is another member of coreutils. I know this doesn't fix the problem with echo, but it should give you the output you desire!

change #!/usr/sh to #!/usr/bash if you are running it inside a script.

You may Add this separator:

echo nl2br("\n");

<?php
$uname="bob";
$uid="1";
$fullname="bobby";
$homedirectory="/sbin";
echo $uname ." ".  $uid  ." ". $fullname ." ".  $homedirectory;
echo nl2br("\n");
$uname="max";
$uid="2";
$fullname="maxwell";
$homedirectory="/bin";
echo $uname  ." ". $uid  ." ". $fullname  ." ". $homedirectory;
?>

You can use simple echo command for this.

echo $uname."<br>".$uid."<br>".$fullname."<br>".$homedirectory."<br>";