UIColor from hex string representation

any snippet to get from:

NSS开发者_如何学JAVAtring *_s = @"#000000";

to:

[UIColor blackColor];

any help is highly appreciated, just been messing around with an ugly code to do this :(

A modified version - also takes an Alpha value

#define UIColorFromRGBA(rgbValue) [UIColor colorWithRed:((float)((rgbValue & 0xFF000000) >> 24))/255.0 green:((float)((rgbValue & 0xFF0000) >> 16))/255.0 blue:((float)((rgbValue & 0xFF00) >> 8 ))/255.0 alpha:((float)((rgbValue & 0xFF))/255.0)]

This works for me:

#define UIColorFromRGB(rgbValue) \
[UIColor \
colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 \
green:((float)((rgbValue & 0x00FF00) >> 8))/255.0 \
blue:((float)(rgbValue & 0x0000FF))/255.0 \
alpha:1.0]

Use it like:

UIColorFromRGB(0x4c4c4c)

I wrote a category on UIColor that accomplishes this:

Create a new Objective-C category. In your header:

#define UIColorFromRGB(rgbValue) [UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 green:((float)((rgbValue & 0xFF00) >> 8))/255.0 blue:((float)(rgbValue & 0xFF))/255.0 alpha:1.0]

@interface UIColor (Hex)

+ (UIColor*)colorFromHex:(NSString*)hex;

@end

And in your implementation:

@implementation UIColor (Hex)

+ (UIColor*)colorFromHex:(NSString *)hex
{
    unsigned result = 0;
    NSScanner *scanner = [NSScanner scannerWithString:hex];

    [scanner setScanLocation:0];
    [scanner scanHexInt:&result];

    return UIColorFromRGB(result);
}

@end

This assume your hex string is in the format 000000, but you can adjust to to your needs to account for a # (change [scanner setScanLocation:0] to [scanner setScanLocation:1]).