getting the starting address of stack [duplicate]

This question already has an answer here: Closed 11 years ago.

Possible Duplicate:

executing assembly within a function in c++

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long getesp() {  
__asm__("movl %esp,%eax");  
}  

void main() {  
printf("%08X\n",getesp()+4);  
}  

why is the esp printed is before the stack is set up?(before the pushl %ebp, movl %esp,%ebp) thanks in advance

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My guess: there is no need for a frame, so none is allocated in getesp. The particulars depend on the compiler and compiler flags you are using.