How to make greedy regex for heading text? [as against tailing text]

Consider the following text:

<bla><bla text><bla>

I want to get the regex to match exactly the middle <bla text>. I tried \<.*?开发者_Python百科text.*?\> but it is capturing the string right from the start, since it starts with '<'.

Thanks a lot.

What do you think about

\<[^>]*text[^>]*?\>

Just not capture any character using ., capture anything but > using [^>]* before and after your "text".

See here on Regexr

This regex matches the central <bla text> and captures it as the first match (brackets included):

(\<\w+? \w+?\>)

Explained, it matches:

• a <
• then, any non-empty sequence of word characters (\w is the shorthand for [a-zA-z_])
• then exactly one space
• then another "greedy" sequence of word chars
• a final >

That is, it matches exactly two words separated by exactly one space, all enclosed in <..>.

This one:

(\<\w+?\s+\w+?\>)

also matches any number of spaces between the two words.

Finally, this one:

<\w+?>(\<\w+? \w+\>)<\w+?>

matches all the string, but captures the content of the central block, so that, if you want to replace the <bla><bla text><bla> string, you may refer to the central block using $1 or \1 in your replacement string.

Here is your regexp.

/>(<bla.*?>)/