passing out parameter
I wrote a method with an out parameter:
-(NSString *)messageDecryption:(NSString *)receivedMessage outParam:(out)messageCondent
{
messageCondent = [receivedMessage substringFromIndex:2];
return [receivedMessage substri开发者_运维问答ngToIndex:1];
}
Then I passed the param like this:
NSString *messageCondent;
NSString *mode = [myclassobject messageDecryption:message outParam:messageCondent];
However, there is a problem. The out parameter value is not being set properly. Can any one help me to do this correctly?
Create the method to accept a pointer to the object.
-(NSString *)messageDecryption:(NSString *)receivedMessage outParam:(NSString**)messageCondent
{
*messageCondent = [receivedMessage substringFromIndex:2];
return [receivedMessage substringToIndex:1];
}
Pass in the reference to the local object.
NSString *messageCondent = nil;
NSString *mode = [myclassobject messageDecryption:message outParam:&messageCondent];
An "out parameter" is by definition a pointer to a pointer.
Your method should look like this:
-(NSString *)messageDecryption:(NSString *)receivedMessage outParam:(NSString **)messageCondent
{
*messageCondent = [receivedMessage substringFromIndex:2];
return [receivedMessage substringToIndex:1];
}
This dereferences the passed-in pointer to get at the actual object reference and then assigns that to whatever [receivedMessage substringFromIndex:2]
returns.
Invoking this method is quite simple:
NSString *messageCondent = nil;
NSString *mode = [myclassobject messageDecryption:message outParam:&messageCondent];
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