Limit 2 digits only from a hash code

I have this $img['hash'] which is a long hash code 32-64 digits a09806aa003033128f44d5fd4c56786b (as an example) Is there any way in php to pull only the 1st two digits (a0)

<?php
$cdb = new PDO('mysql:dbname=xxx;host=localhost', 'xxx', 开发者_如何学Python'xxx');

foreach ($cdb->query("SELECT * FROM images ORDER BY posted DESC LIMIT 9") AS $img)
{
    echo '<a style="position: relative; display: block; height: 200px;" href="/booru/post/view/' . $img['id'] . '" target="_blank">
          <img src="booru/timthumb.php?src=thumbs/' . $img['hash'] . '&h=125&w=125" style="border-style: none"/>
           </a> 
        ';
}

Sorry I should of added some more info I need to keep the $img['hash'] also

So like this

                <img src="booru/timthumb.php?src=thumbs/' . $img['hash'] . '/Here/&h=125&w=125" width="125px" style="border-style: none"/>

I need to add it where the "/here/" is

You can use substr() to get a substring of a string, in this case your hash:

$twofirst = substr($img['hash'], 0, 2);

Try:

substr($img['hash'], 0, 2);

Yes, use substr:

echo '<img src="...' . substr($img['hash'], 0, 2) . '" />';

You can use php's substr method (http://php.net/manual/en/function.substr.php) and output:

substr($img['hash'), 0, 2)

Which will output the first 2 digits, starting at index 0, of the $img['hash'] string.

In PHP you can use substr http://php.net/manual/en/function.substr.php

substr(img['hash'], 0, 2)

should do the trick