php array return

Ok, function:

function session_login_name($username) {
                global $myDB;
                global $config;
                $query = "SELECT /* page == login, functions.php */id, username FROM members WHERE username = '".$username."' LIMIT 1";
                $result = $myDB->Execute($query) or die(GetDbError($myDB->ErrorMsg()));
                $nick_show = $result->Fields("username");
                $nick_id = $result->Fields("id");
                $arr = array($nick_show, $nick_id);
                return $arr;
}

In next file i need describe:

$_SESSION['userid'] = ;   //user id
$_SESSION['username'] = ; //user name

How do I do that? If question unclear, just s开发者_如何学编程ay it... Oh, and print_r ($arr) gives: Array ( [0] => zero [1] => 4 )

I have tried (guessed), but that of course isn't correct :/

echo session_login_name($username[0]);
die();

You said print_r ($arr) gives: Array ( [0] => zero [1] => 4 ) so you just need to get those value and assign them to the session variables:

// ToDo: fix SQL injection vulnerability in your SQL
$Data = session_login_name($username);
$_SESSION['userid'] = $Data[1];   //user id
$_SESSION['username'] = $Data[0]; //user name

$nick_show = $result->Fields("username");
$nick_id = $result->Fields("id");
$arr['userid'] = $nick_id;   //user id
$arr['username'] = $nick_show; //user name
return $arr;

well you cant echo an array it will print array() on the screen

where did you define $username ?

well simply read the values of the array