Proper way to use AJAX Post in jquery to pass model from strongly typed MVC3 view
I'm a novice web programmer 开发者_如何学运维so please forgive me if some of my "jargon" is not correct. I've got a project using ASP.NET using the MVC3 framework.
I am working on an admin view where the admin will modify a list of equipment. One of the functions is an "update" button that I want to use jquery to dynamically edit the entry on the webpage after sending a post to the MVC controller.
I presume this approach is "safe" in a single admin setting where there is minimal concern of the webpage getting out of sync with the database.
I've created a view that is strongly typed and was hoping to pass the model data to the MVC control using an AJAX post.
In the following post, I found something that is similar to what I am looking at doing: JQuery Ajax and ASP.NET MVC3 causing null parameters
I will use the code sample from the above post.
Model:
public class AddressInfo
{
public string Address1 { get; set; }
public string Address2 { get; set; }
public string City { get; set; }
public string State { get; set; }
public string ZipCode { get; set; }
public string Country { get; set; }
}
Controller:
public class HomeController : Controller
{
public ActionResult Index()
{
return View();
}
[HttpPost]
public ActionResult Check(AddressInfo addressInfo)
{
return Json(new { success = true });
}
}
script in View:
<script type="text/javascript">
var ai = {
Address1: "423 Judy Road",
Address2: "1001",
City: "New York",
State: "NY",
ZipCode: "10301",
Country: "USA"
};
$.ajax({
url: '/home/check',
type: 'POST',
data: JSON.stringify(ai),
contentType: 'application/json; charset=utf-8',
success: function (data.success) {
alert(data);
},
error: function () {
alert("error");
}
});
</script>
I have not had a chance to use the above yet. But I was wondering if this was the "best" method to pass the model data back to the MVC control using AJAX?
Should I be concerned about exposing the model information?
I found 3 ways to implement this:
C# class:
public class AddressInfo {
public string Address1 { get; set; }
public string Address2 { get; set; }
public string City { get; set; }
public string State { get; set; }
public string ZipCode { get; set; }
public string Country { get; set; }
}
Action:
[HttpPost]
public ActionResult Check(AddressInfo addressInfo)
{
return Json(new { success = true });
}
JavaScript you can do it three ways:
1) Query String:
$.ajax({
url: '/en/Home/Check',
data: $('#form').serialize(),
type: 'POST',
});
Data here is a string.
"Address1=blah&Address2=blah&City=blah&State=blah&ZipCode=blah&Country=blah"
2) Object Array:
$.ajax({
url: '/en/Home/Check',
data: $('#form').serializeArray(),
type: 'POST',
});
Data here is an array of key/value pairs :
=[{name: 'Address1', value: 'blah'}, {name: 'Address2', value: 'blah'}, {name: 'City', value: 'blah'}, {name: 'State', value: 'blah'}, {name: 'ZipCode', value: 'blah'}, {name: 'Country', value: 'blah'}]
3) JSON:
$.ajax({
url: '/en/Home/Check',
data: JSON.stringify({ addressInfo:{//missing brackets
Address1: $('#address1').val(),
Address2: $('#address2').val(),
City: $('#City').val(),
State: $('#State').val(),
ZipCode: $('#ZipCode').val()}}),
type: 'POST',
contentType: 'application/json; charset=utf-8'
});
Data here is a serialized JSON string. Note that the name has to match the parameter name in the server!!
='{"addressInfo":{"Address1":"blah","Address2":"blah","City":"blah","State":"blah", "ZipCode", "blah", "Country", "blah"}}'
You can skip the var declaration and the stringify. Otherwise, that will work just fine.
$.ajax({
url: '/home/check',
type: 'POST',
data: {
Address1: "423 Judy Road",
Address2: "1001",
City: "New York",
State: "NY",
ZipCode: "10301",
Country: "USA"
},
contentType: 'application/json; charset=utf-8',
success: function (data) {
alert(data.success);
},
error: function () {
alert("error");
}
});
This is the way it worked for me:
$.post("/Controller/Action", $("#form").serialize(), function(json) {
// handle response
}, "json");
[HttpPost]
public ActionResult TV(MyModel id)
{
return Json(new { success = true });
}
what you have is fine - however to save some typing, you can simply use for your data
data: $('#formId').serialize()
see http://www.ryancoughlin.com/2009/05/04/how-to-use-jquery-to-serialize-ajax-forms/ for details, the syntax is pretty basic.
If using MVC 5 read this solution!
I know the question specifically called for MVC 3, but I stumbled upon this page with MVC 5 and wanted to post a solution for anyone else in my situation. I tried the above solutions, but they did not work for me, the Action Filter was never reached and I couldn't figure out why. I am using version 5 in my project and ended up with the following action filter:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using System.Web.Mvc.Filters;
namespace SydHeller.Filters
{
public class ValidateJSONAntiForgeryHeader : FilterAttribute, IAuthorizationFilter
{
public void OnAuthorization(AuthorizationContext filterContext)
{
string clientToken = filterContext.RequestContext.HttpContext.Request.Headers.Get(KEY_NAME);
if (clientToken == null)
{
throw new HttpAntiForgeryException(string.Format("Header does not contain {0}", KEY_NAME));
}
string serverToken = filterContext.HttpContext.Request.Cookies.Get(KEY_NAME).Value;
if (serverToken == null)
{
throw new HttpAntiForgeryException(string.Format("Cookies does not contain {0}", KEY_NAME));
}
System.Web.Helpers.AntiForgery.Validate(serverToken, clientToken);
}
private const string KEY_NAME = "__RequestVerificationToken";
}
}
-- Make note of the using System.Web.Mvc
and using System.Web.Mvc.Filters
, not the http
libraries (I think that is one of the things that changed with MVC v5. --
Then just apply the filter [ValidateJSONAntiForgeryHeader]
to your action (or controller) and it should get called correctly.
In my layout page right above </body>
I have @AntiForgery.GetHtml();
Finally, in my Razor page, I do the ajax call as follows:
var formForgeryToken = $('input[name="__RequestVerificationToken"]').val();
$.ajax({
type: "POST",
url: serviceURL,
contentType: "application/json; charset=utf-8",
dataType: "json",
data: requestData,
headers: {
"__RequestVerificationToken": formForgeryToken
},
success: crimeDataSuccessFunc,
error: crimeDataErrorFunc
});
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