copying c char pointer to a non pointer char

Is there any problem on doing that?

char* field = new char[2];开发者_如何学运维
field[0] = 'S';
field[1] = '\0';

char c = *field;

will c always be equal to 'S'?

No problem with that, c will always be 'S'.

This is totally fine - and c will always be equal to 'S'. Dereferencing field, a pointer of type char will result in a char.

There is a problem in that new char[2] is not C syntax. The general idea is correct, though: c will always be 'S'.

There's nothing wrong with that. When you dereference the field array in the line

char c = *field;

what you're actually asking is for the value of the first element of the array, in this case 'S'.