How to convert 1D array to 2D by column major
say I have a 1D array like int[] x = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}
.
1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16
Currently, I have
for (int i = 0; i < 4; i++)
{
for (int j = 0; j < Nb; j++)开发者_Python百科
s[i][j] = x[i + j];
}
However, that doesnt work. How would I do this?
Try
for (int i = 0, k=0; i < 4; i++)
for (int j = 0; j < Nb; j++)
s[j][i] = x[k++]; // you may want s[i][j]
I assume that stray 7
was a typo?
Since we want the inner loop to move downward, and the outer to move rightward, you can do this:
for i in (0..width)
for j in (0..height)
s[j][i] = x[i*height+j]
Tracing this out illustrates why it works:
s[0][0] = x[0*4+0] = x[0]
s[1][0] = x[0*4+1] = x[1]
...
s[0][1] = x[1*4+1] = x[5]
No clue what Nb
is, but you're way off on reading the initial array. Try something like this:
for (int i = 0; i < 4; i++)
for (int j = 0; j < 4; j++)
s[j][i] = x[i*4 + j];
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