Finding type in python - TypeError 'unicode' object is not callable
I'm trying to make sure an object is a string type in Python (for google app engine). I'm doing this so that I can change it to a db.Text
type if its more than 500 bytes. However, I keep getting the error: TypeError 'unicode' object is not callable
开发者_运维知识库 if type(value) in types.StringTypes and len(value) > 499:
value = db.Text(value)
setattr(entity, key, value)
What should I use to test if the type of the object is a string?
I think you just need to remove the parentheses from types.StringTypes
, since it is a tuple (and not callable, hence the error). Either that, or your code is actually using StringType
, which means your code is making a new string instance instead of returning the str
type. Either way, it looks like a typo. See the docs.
Why are you calling types.StringTypes
? It's a tuple:
>>> types.StringTypes
(<type 'str'>, <type 'unicode'>)
Use isinstance(value, types.StringTypes) and len(value) > 499
Greg Haskins is right
>>> types.StringTypes()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'tuple' object is not callable
>>> types.StringTypes
(<type 'str'>, <type 'unicode'>)
Could you do
if type(variable_name) == type("")
Edit: Oops! I was looking at types.StringType, instead of types.StringTypes, so the test could be:
if type(value) in types.StringTypes and len(value) > 499:
value = db.Text(value)
Where the main problem with the OP code was the presence of the parens at the end of types.StringTypes.
Original: A few problems here:
- If value holds a Unicode, testing it with type() will return types.UnicodeType
- The types.StringType is a constant, not a function, so drop the parentheses.
- Furthermore, types.StringType isn't iterable, so test against it with == or is.
Thus, your test could look something like:
if ((type(value) == types.StringType) or (type(value) == types.UnicodeType)) and len(value) > 499:
value = db.Text(value)
I prefer
isinstance(object_to_be_checked, str)
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