How to submit a form with AJAX and return a summary of the input values

I have a multipart form and am using the jQuery form plugin.

When a user completes a section of the form and clicks "continue," I would like to send that information to the server and then provide a summary of the submitted information on the same page. With my current code, I get an error unless all of the fields are completed before submission. My guess is that my PHP is completely wrong and that the information I have entered after "data:" is also incorrect.

Any suggestions on how to make this work properly?

PHP:

$return['message'] = array(); 

if ($_POST['markName1']) {
$return['message'][]='Text' . $_POST['markName1'];
}

if ($_POST['markDescription1']) {
$return['message'][]='More text' . $_POST['markDescription1'];
}

 if ($_POST['YesNo1']) {
$return['message'][]='' . $_POST['YesNo1'];
}

echo json_encode($return);

jQuery:

$(form).ajaxSubmit({                
   type: "POST",
   data: {
          "markName1" : $('#markName1').val(),
          "markDescription1" : $('#markDescription1').val()
                       },
   dataType: 'json',
   url: './includes/ajaxtest3.php',
 //...
   error: function() {alert("error!");},                    
   success: $('#output2').html(data.message.join('<br />'))
//...

HTML:

<form id="mark-form">
 <div class="markSe开发者_开发百科lection">
    <input type="checkbox" >
      <label for="standardCharacter"></label>
              <span class="markName-field field">
                <label for="markName1" ></label>
                <input type="text" name="markName1" id="markName1">
              </span>   
         <label for="markDescription1"></label>
         <textarea id="markDescription1" name="markDescription1"></textarea>
       <ul class="YesNo">
         <li>
           <input type="radio" name="YesNo1" value="Yes">
             <label for="Yes">Yes</label>
         </li>
         <li>
           <input type="radio" name="YesNo1" value="No">
           <label for="No">No</label>
         </li>
       </ul>
  </div>
  <div class="step-section">
    <p>
    <span class="next-step">
      <button id="submit-second" class="submit" type="submit" name="next">Next</button>
    </span>
   </p>
 </div>
</form> 

You dont need quotes around this markName1:$('#markName1').val() or markDescription1 : $('#markDescription1').val()

Try putting this for your success callback

success: function(html) {
        alert(html);
    }

You should change your PHP to this:

$markName1 = $_POST['markName1'];
$markDescription1 = $_POST['markDescription1'];
$YesNo1 = $_POST['YesNo1'];

if(!empty($markName1)){
echo 'Text' . $markName1;
}
if(!empty($markDescription1)){
echo 'More Text' . $markDescription1;
}
if(!empty($YesNo1)){
echo $YesNo1;
}

Note I changed the success function data type to html

EDIT 2

create a button outside the <form> and replace your ajax with this:

$('#submit-button').click(function() {
    $.post('./includes/ajaxtest3.php', $('#mark-form').serialize(), function(html) {
        document.getElementById('someDiv').write(html);
    }
    });