开发者

javascript date to string

Here is what I need to do.

Get Date, convert to string and pass it over to a third party uti开发者_如何学运维lity. The response from the library will have date in string format as I passed it. So, I need to convert the date to string like 20110506105524 (YYYYMMDDHHMMSS)

function printDate() {
    var temp = new Date();
    var dateStr = temp.getFullYear().toString() + 
                  temp.getMonth().toString() + 
                  temp.getDate().toString() +
                  temp.getHours().toString() + 
                  temp.getMinutes().toString() + 
                  temp.getSeconds().toString();

    debug (dateStr );
}

The problem with above is that for months 1-9, it prints one digit. How can I change it to print exactly 2 digits for month, date ...


You will need to pad with "0" if its a single digit & note that getMonth returns 0..11 not 1..12

function printDate() {
  const temp = new Date();
  const pad = (i) => (i < 10) ? "0" + i : "" + i;

  return temp.getFullYear() +
    pad(1 + temp.getMonth()) +
    pad(temp.getDate()) +
    pad(temp.getHours()) +
    pad(temp.getMinutes()) +
    pad(temp.getSeconds());
}

console.log(printDate());


Relying on JQuery Datepicker, but it could be done easily:

var mydate = new Date();
$.datepicker.formatDate('yy-mm-dd', mydate);


use this polyfill https://github.com/UziTech/js-date-format

var d = new Date("1/1/2014 10:00 am");
d.format("DDDD 'the' DS 'of' MMMM YYYY h:mm TT");
//output: Wednesday the 1st of January 2014 10:00 AM


I like Daniel Cerecedo's answer using toJSON() and regex. An even simpler form would be:

var now = new Date();
var regex = /^(\d{4})-(\d{2})-(\d{2})T(\d{2}):(\d{2}):(\d{2}).*$/;
var token_array = regex.exec(now.toJSON());
// [ "2017-10-31T02:24:45.868Z", "2017", "10", "31", "02", "24", "45" ]
var myFormat = token_array.slice(1).join('');
// "20171031022445"


A little bit simpler using regex and toJSON().

var now = new Date();
var timeRegex = /^.*T(\d{2}):(\d{2}):(\d{2}).*$/
var dateRegex = /^(\d{4})-(\d{2})-(\d{2})T.*$/
var dateData = dateRegex.exec(now.toJSON());
var timeData = timeRegex.exec(now.toJSON());
var myFormat = dateData[1]+dateData[2]+dateData[3]+timeData[1]+timeData[2]+timeData[3]

Which at the time of writing gives you "20151111180924".

The good thing of using toJSON() is that everything comes already padded.


Maybe it is easier to convert the Date into the actual integer 20110506105524 and then convert this into a string:

function printDate() {
    var temp = new Date();
    var dateInt =
        ((((temp.getFullYear() * 100 + 
            temp.getMonth() + 1) * 100 + 
           temp.getDate()) * 100 +
          temp.getHours()) * 100 + 
         temp.getMinutes()) * 100 + 
        temp.getSeconds();

    debug ( '' + dateInt );  // convert to String
}

When temp.getFullYear() < 1000 the result will be one (or more) digits shorter.

Caution: this wont work with millisecond precision (i.e. 17 digits) since Number.MAX_SAFE_INTEGER is 9007199254740991 which is only 16 digits.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜