开发者

INT32U and INT8U in Objective C

I am getting errors withis below declaration.when declared INT32U i'm getting errors.

Though INT32U and int are 4 bytes.How will i declare the equivalent of INT8U.I cant use int here as its INT8U is 2 bytes.

INT32U_C Uucode(IN开发者_运维百科T8U_C* pDst,const INT8U_C* pSrc,INT32U_C nSrcLen);

Error:Expected '=',','";" 'asm' or 'attribute' before Uucode.


stdint.h has specific-size integer definitions, including uint32_t and uint8_t.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜