How to change headers level by XSLT based on depth in XML
My XSL-file:
...
<div>
<xsl:choose>
<xsl:when test="count(ancestor::node()) = 1">
<h2>
</xsl:when>
<xsl:when test="count(ancestor::node()) = 2">
<h3>
</xsl:when>
</xsl:choose>
<xsl:attribute name="id">
<xsl:value-of select="@id" />
</xsl:attribute>
<xsl:copy-of select="title/node()"/>
<xsl:choose>
<xsl:when test="count(ancestor::node()) = 1">
</h2>
</xsl:when>
<xsl:when test="count(ancestor::node()) = 2">
</h3>
</xsl:when&开发者_StackOverflowgt;
</xsl:choose>
</div>
I know that it is not allowed to split tags h2.../h2, h3.../h3 like this.
But how to do this correctly?
You could do this with a recursive template and generate the heading element dynamically.
For example, this input XML:
<input>
<level id="1">
<title>first</title>
<level id="2">
<title>second</title>
<level id="3">
<title>third</title>
</level>
</level>
</level>
</input>
processed by this XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" exclude-result-prefixes="xsl">
<xsl:output omit-xml-declaration="yes" indent="yes" method="html"/>
<xsl:strip-space elements="*"/>
<xsl:template match="level">
<xsl:variable name="level" select="count(ancestor-or-self::level) + 1"/>
<xsl:element name="h{$level}">
<xsl:attribute name="id">
<xsl:value-of select="@id"/>
</xsl:attribute>
<xsl:copy-of select="title/node()"/>
</xsl:element>
<xsl:apply-templates select="level"/>
</xsl:template>
</xsl:stylesheet>
gives the following HTML:
<h2 id="1">first</h2>
<h3 id="2">second</h3>
<h4 id="3">third</h4>
You could use
<xsl:template match="/div">
<h1><xsl:apply-templates/></h1>
</xsl:template>
<xsl:template match="/*/div">
<h2><xsl:apply-templates/></h2>
</xsl:template>
<xsl:template match="/*/*/div">
<h3><xsl:apply-templates/></h3>
</xsl:template>
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