Is there anyway to handy convert a dictionary to String?
I foun开发者_运维问答d the default implemtation of ToString in the dictionary is not what I want. I would like to have {key=value, ***}
.
Any handy way to get it?
If you just want to serialize for debugging purposes, the shorter way is to use String.Join
:
var asString = string.Join(Environment.NewLine, dictionary);
This works because IDictionary<TKey, TValue>
implements IEnumerable<KeyValuePair<TKey, TValue>>
.
Example
Console.WriteLine(string.Join(Environment.NewLine, new Dictionary<string, string> {
{"key1", "value1"},
{"key2", "value2"},
{"key3", "value3"},
}));
/*
[key1, value1]
[key2, value2]
[key3, value3]
*/
Try this extension method:
public static string ToDebugString<TKey, TValue> (this IDictionary<TKey, TValue> dictionary)
{
return "{" + string.Join(",", dictionary.Select(kv => kv.Key + "=" + kv.Value).ToArray()) + "}";
}
How about an extension-method such as:
public static string MyToString<TKey,TValue>
(this IDictionary<TKey,TValue> dictionary)
{
if (dictionary == null)
throw new ArgumentNullException("dictionary");
var items = from kvp in dictionary
select kvp.Key + "=" + kvp.Value;
return "{" + string.Join(",", items) + "}";
}
Example:
var dict = new Dictionary<int, string>
{
{4, "a"},
{5, "b"}
};
Console.WriteLine(dict.MyToString());
Output:
{4=a,5=b}
Maybe:
string.Join
(
",",
someDictionary.Select(pair => string.Format("{0}={1}", pair.Key.ToString(), pair.Value.ToString())).ToArray()
);
First you iterate each key-value pair and format it as you'd like to see as string, and later convert to array and join into a single string.
No handy way. You'll have to roll your own.
public static string ToPrettyString<TKey, TValue>(this IDictionary<TKey, TValue> dict)
{
var str = new StringBuilder();
str.Append("{");
foreach (var pair in dict)
{
str.Append(String.Format(" {0}={1} ", pair.Key, pair.Value));
}
str.Append("}");
return str.ToString();
}
I got this simple answer.. Use JavaScriptSerializer
Class for this.
And you can simply call Serialize method with Dictionary object as argument.
Example:
var dct = new Dictionary<string,string>();
var js = new JavaScriptSerializer();
dct.Add("sam","shekhar");
dct.Add("sam1","shekhar");
dct.Add("sam3","shekhar");
dct.Add("sam4","shekhar");
Console.WriteLine(js.Serialize(dct));
Output:
{"sam":"shekhar","sam1":"shekhar","sam3":"shekhar","sam4":"shekhar"}
If you want to use Linq, you could try something like this:
String.Format("{{{0}}}", String.Join(",", test.OrderBy(_kv => _kv.Key).Zip(test, (kv, sec) => String.Join("=", kv.Key, kv.Value))));
where "test" is your dictionary. Note that the first parameter to Zip() is just a placeholder since a null cannot be passed).
If the format is not important, try
String.Join(",", test.OrderBy(kv => kv.Key));
Which will give you something like
[key,value], [key,value],...
Another solution:
var dic = new Dictionary<string, double>()
{
{"A", 100.0 },
{"B", 200.0 },
{"C", 50.0 }
};
string text = dic.Select(kvp => kvp.ToString()).Aggregate((a, b) => a + ", " + b);
Value of text: [A, 100], [B, 200], [C, 50]
You can loop through the Keys of the Dictionary and print them together with the value...
public string DictToString(Dictionary<string, string> dict)
{
string toString = "";
foreach (string key in dict.Keys)
{
toString += key + "=" + dict[key];
}
return toString;
}
I like ShekHar_Pro's approach to use the serializer. Only recommendation is to use json.net to serialize rather than the builtin JavaScriptSerializer since it's slower.
I really like solutions with extension method above, but they are missing one little thing for future purpose - input parametres for separators, so:
public static string ToPairString<TKey, TValue>(this Dictionary<TKey, TValue> dictionary, string pairSeparator, string keyValueSeparator = "=")
{
return string.Join(pairSeparator, dictionary.Select(pair => pair.Key + keyValueSeparator + pair.Value));
}
Example of using:
string result = myDictionary.ToPairString(Environment.NewLine, " with value: ");
What you have to do, is to create a class extending Dictionary
and overwrite the ToString()
method.
See you
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