XSL for <schema xmlns="http://www.w3.org/2001/XMLSchema">

What will be the equivalent XSL style sheet f开发者_如何学Goor <schema xmlns="http://www.w3.org/2001/XMLSchema">

Update: The OP provided his code.

Use:

<xsl:for-each select="x:schema/x:element">

Instead of:

<xsl:for-each select="schema/element">

Search/read about "default namespace in XPath". This is a F A Q

This transformation:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:x="http://www.w3.org/2001/XMLSchema">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="/">
     <xsl:value-of select="/x:schema/x:a/x:b/x:c"/>
 </xsl:template>
</xsl:stylesheet>

when applied on this XML document:

<schema xmlns="http://www.w3.org/2001/XMLSchema">
 <a>
  <b>
   <c>d</c>
  </b>
 </a>
</schema>

produces the wanted result:

d

Explanation: Any unprefixed name in an XPath expression is always considered to be in "no namespace". If the XML document has a default namespace, then any element of this document is in the default namespace (not in "no namespace). Therefore, for such a document unprefixed names don't select any node -- because not a single node in this document is in "no namespace".