mysql fetch array error? [duplicate]
Possible Duplicate:
mysql_fetch_array() expects parameter 1 to be resource, boolean given in select
I am getting Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\FBlike\like.php on line 104 in my script..
I'm not sure what that means and why it is happening.. help :)?
$like_id=mysql_real_escape_string($_GET['id']);
$sql=mysql_query("select * from likes WHERE id=$like_id DESC LIMIT 1");
while($row=mysql_fetch_array($sql))
{
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<met开发者_C百科a name="description" content="<?php print $row['like']; ?>"/>
<meta name="keywords" content="<?php print $row['like']; ?>" />
<meta property="og:description" content="Click to See More..." />
<meta property="fb:app_id" content="" />
<meta property="og:title" content="<?php print $row['like']; ?>"/>
<meta property="og:type" content="activity"/>
<meta property="og:url" content="http://www.fbquote.me/like.php?id=<?php print $row['id']; ?>" />
<meta property="og:site_name" content="pDank" />
<title><?php print $row['like']; ?></title>
<?php } ?>
mysql_query() returns FALSE on error, ergo you have an error in your query.
Use mysql_error() to get the last error message.
For example
$result = mysql_query("select * from likes WHERE id=$like_id DESC LIMIT 1");
if (false === $result) {
throw new Exception('MySQL error: ' . mysql_error());
}
You have an error in your SQL query.
Add the following code before mysql_fetch_array():
if (!$sql) {
die(mysql_error());
}
That means your query failed for some reason (invalid syntax, column not found...) and returned FALSE.
To capture that, check if $sql (actually, you should name that variable $result or similar, that is much more common ($sql is typically used for query strings)) is FALSE and if so, print/log whatever the function mysql_error() returns.
加载中,请稍侯......
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