How to Google Mock a method called from a struct

Let's have this example:

    Class A{
         public:
           int Get();
   }

In another file:

A a;
struct B{
    int res = a.Get(); 
}

I would need to Googl开发者_JS百科e Mock Get method, however, I will also need to call the real one. I have tried with #ifdef, and it seems to work. Then I decided to mock it in the #ifdef section but it does nothing.

#ifdef UNIT_TEST
MOCK_METHOD0(A,Get);
#else
int A::Get(){....}
#endif

What am I doing wrong? Is there any cleaner way to do it? Please, any help would be much appreciate it.

You did it wrongly. This is how it should be done :

1) Header file :

    struct A
    {
   #ifdef UNIT_TEST
       MOCK_METHOD0(Get, int());
   #else
       int Get();
   #endif
    };

2) Source file :

#ifndef UNIT_TEST
int A::Get()
{
  // ...
}
#endif

It seems that Google Mock has changed quite a bit. Now you can try delegating to a real object described in the cookbook. You can continue setting and checking expectations on your mock, but the calls will also be handled by the real thing.

class MockA : public A
{
public:
    MockA()
    {
        ON_CALL(*this, Get()).WillByDefault(Invoke(&real, &A::Get));
    }
    MOCK_METHOD0(Get, int());

private:
    A real;
};

Header file:

class A{
     public:
       int Get();
};
A a;

Source file:

int A::Get(){
   ....
}

struct B{
    return res = a.Get();
};