bash shell script

I have $L开发者_JAVA百科IST variable that contains few lines and some of the lines has spaces, but I need to take that as one vs two arguments inside of my loop, how would I do that?

\#!/bin/bash

LIST="test1
test 2"

for i in $LIST; do
 echo $i;
done

this will produce me 3 lines, but I want it to produce 2 as test1 on first line and test 2 on second

#!/bin/bash
LIST="test1
test 2"

while read i
do
    echo "[$i]"
done <<< "$LIST"

Thanks to [] characters we can see that the loop was evaluated twice.

IFS controls what's treated as a word break when variables are expanded (e.g. in the for command):

LIST="test1
test 2"

saveIFS="$IFS"; IFS=$'\n'
for i in $LIST; do
    IFS="$saveIFS" # This is only needed if something in the loop depends on IFS
    echo "$i"
done
IFS="$saveIFS"

Just for fun and educational purposes: No need for bashisms like <<< here. Understand that echo keeps newlines in quoted strings and just read line by line as follows:

#!/bin/sh

LIST="test1
test 2"

echo "$LIST" |
while read -r line; do
  echo "[$line]"
done

$ ./x.sh
[test1]
[test 2]

There, 100% POSIX shell compatible!

No need to change IFS. Just need to quote your variable

LIST="test1
test 2"

for i in "$LIST"; do
 echo "$i";
done