How to vibrate device n number of times through programming in android?
can anyone tell me how to vibrate same patter 5 times like this my pattern
开发者_如何学Pythonlong[] pattern = { 0, 200, 500 };
i want this pattern to repeat 5 times
Vibrator vibrator = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);
vibrator.vibrate(pattern , 5);
I found the solution, it was very simple:
long[] pattern = { 0, 100, 500, 100, 500, 100, 500, 100, 500, 100, 500};
vibrator.vibrate(pattern , -1);
From: Android Vibrator#vibrate(long[], int)
To cause the pattern to repeat, pass the index into the pattern array at which to start the repeat, or -1 to disable repeating.
You have to init index 0
long[] pattern = { 0, 100, 500, 100, 500, 100, 500, 100, 500, 100, 500};
vibrator.vibrate(pattern , 0);
the following works for me:
if(vibration_enabled) {
final Vibrator v = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);
if(v.hasVibrator()) {
final long[] pattern = {0, 1000, 1000, 1000, 1000};
new Thread(){
@Override
public void run() {
for(int i = 0; i < 5; i++){ //repeat the pattern 5 times
v.vibrate(pattern, -1);
try {
Thread.sleep(4000); //the time, the complete pattern needs
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}.start();
}
}
The vibrate method only starts the vibration, but doesn't wait until its executed.
Your code should do the trick. Just make sure you have
<uses-permission android:name="android.permission.VIBRATE"/>
in the AndroidManifest.xml
file.
Besides the above given solutions, i have created my own vibration pattern where i can control the duration size between vibrations. startVibration() creates a continous regular vibration pattern for one minute.
stopVibration() - Terminates the vibration or pauses the counterTimer thus pausing the vibration pattern.
private time = 0;
private countDownTimer;
private void startVibration() {
time = (int) System.currentTimeMillis();
countDownTimer = new CountDownTimer(60000, 1000) {
public void onTick(long millisUntilFinished) {
time = (int) (millisUntilFinished / 1000);
int[] timeLapse = {58, 55, 52, 49, 46, 43, 40, 37, 34, 31, 28, 25, 22, 19, 16, 13, 10, 7, 4, 1};
for (int k = 0; k < timeLapse.length; k++) {
if (time == timeLapse[k]) {
((Vibrator) getSystemService(VIBRATOR_SERVICE)).vibrate(1000);
}
}
}
public void onFinish() {
}
}.start();
}
private void stopVibration() {
if (countDownTimer != null) {
countDownTimer.cancel();
}
}
In the method public void vibrate (long[] pattern, int repeat), the long[] pattern follows the rule : long[] pattern = {pauseTime1, vibrationTime1, pauseTime2, vibrationTime2, pauseTime3, vibrationTime3, ...} so as a result you have odd number of values, it won't works. You must have to end the pattern with a vibrationTime. An even number of value do the job (at least 4 values).
long[] pattern = {0, 500, 200, 500}
Vibrator vibrator = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);
vibrator.vibrate(pattern , 5);
Here's how I did it. I dynamically generate my timing array based on the number of times the caller wants it to vibrate. In the loop, start at 1 so to avoid 0 % 2 causing an extra useless delay at the end.
private void vibrate(int times)
{
Vibrator vibrator = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O)
{
ArrayList<Long> timings = new ArrayList();
timings.add(0L);
for(int i = 1; i <= times; i ++)
{
if(i%2==0)
timings.add(0L);
timings.add(250L);
}
long[] arrTimings = new long[timings.size()];
for(int j = 0; j < timings.size(); j++)
{
arrTimings[j] = timings.get(j);
}
vibrator.vibrate(VibrationEffect.createWaveform(arrTimings, -1));
}
}
long vibrationDuration = Arrays.stream(pattern).sum();
new CountDownTimer(vibrationDuration*(repeat+1), vibrationDuration) {
@Override
public void onTick(long millisUntilFinished) {
v.cancel();
if (Build.VERSION.SDK_INT >= 26) {
VibrationEffect vibrationEffect = VibrationEffect.createWaveform(pattern, -1);
v.vibrate(vibrationEffect);
} else {
v.vibrate(pattern, -1);
}
}
@Override
public void onFinish() {
v.cancel();
}
}.start();
You can apply one trick, just build pattern dynamic based on number of repetition you want.
private long[] createVibrationPattern(long[] oneShotPattern, int repeat) {
long[] repeatPattern = new long[oneShotPattern.length * repeat];
System.arraycopy(oneShotPattern, 0, repeatPattern, 0, oneShotPattern.length);
for (int count = 1; count < repeat; count++) {
repeatPattern[oneShotPattern.length * count] = 500; // Delay in ms, change whatever you want for each repition
System.arraycopy(oneShotPattern, 1, repeatPattern, oneShotPattern.length * count + 1, oneShotPattern.length - 1);
}
return repeatPattern;
}
Then do the call like below
long[] pattern = { 0, 200, 500 };
Vibrator vibrator = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);
vibrator.vibrate(createVibrationPattern(pattern , 2);
OUTPUT Pattern would become as 0, 200, 500, 500, 0, 200, 500
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