Invoke public function from internal/private function?
Just wondering if I'm missing something or not but I attempted to do the following:
(function() {
var thing = function() {
var doIt = function() {
console.log("just do it");
this.updateValue(5);
};
return {
updateValue: function(val) {
console.log('updating value: ' + val);
},
go: function() {
doIt();
}
}
};
var t = thing();
t.go();
}())
This results in "just do it" showing up in the console followed by an error b/c it says "updateValue" is not a function.
I was wondering, can an internal/private function (e.g. "doIt") invoke a public function (e.g. "updateValue")? Perhaps this is just bad design and you should never really want to do this and I've actually 开发者_StackOverflowrefactored my code to avoid/not do this but I was curious if it was possible.
Thanks in advance.
Either use call/apply to explicitly specify the context for this
(like @SLaks and @Alnitak) mentioned or else define the function at the beginning and then add it as a property to the returned object:
var thing = function() {
var updateValue = function () { /* */ },
doIt = function() {
console.log("just do it");
updateValue(5);
};
return {
updateValue: updateValue, // minor duplication here
go: function() {
doIt();
}
};
};
If the minor duplication annoys you, you can also do this:
var thing = function() {
var exposed = {
updateValue: function(val) {
console.log('updating value: ' + val);
},
go: function() {
doIt();
}
}, doIt = function() {
console.log("just do it");
exposed.updateValue(5);
};
return exposed;
};
Writing doIt()
, calls the function in the global context, so this
is the window
object.
You need to write doIt.call(this)
to pass your this
as the context for doIt
.
Per @SLaks answer, this
is incorrect when invoked by doIt()
.
Instead, try:
doIt.call(this);
精彩评论