Would like not selected radio buttons should return empty string
I have the following HTML
<form id="create_form" name="create_form" action="" method="post">
<input name="type" id="type" value="individuel" type="radio" /> Individuel <br/>
<input name="type" id="type" value="course" type="radio" /> Course <br/>
<button class="n" type="submit">Create</button>
</form>
and when I get the value of the radio buttons, when none have been selected, my JQuery/Ajax script returns the first radio button.
$(document).ready(function(){
$("form#create_form").submit(function() {
var type = $('input:radio[name=type]:checked').val();
...
I would like that the users is forced to consider which to select, and not just the default.
How is that done?
Update:
I would think that
开发者_开发问答$(document).ready(function(){
$("form#create_form").submit(function() {
var type = $('input:radio[name=type]:checked').val();
means to only get the values of the radio buttons in the form with id="create_form"
.
But because I had forms below (with <form id="something_else"
) and radio buttons in those forms also with name="type"
it extracted that value.
Changing name=type
to name=cname
in both html and JQuery solved the problem.
Sounds like a bug in JQuery, doesn't it?
Try defining the variable like this (to get an empty string):
var type = $('input:radio[name=type]:checked').val() || '';
Hmmm, ok to answer the question about making a user choose... try this instead:
var type = $('input:radio[name=type]:checked').val();
if (typeof type === 'undefined') {
alert('You must make a choice!');
return false;
}
if
( ! $("input:radio").is(':checked') )
Doesn't work?
You might also try like so:
var is_checked = true;
$('input:radio').each(function(){
is_checked = is_checked && $(this).is(':checked');
});
if ( ! is_checked );
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