c++ .h and .cpp files - about methods

HI.

How can I define a boo开发者_开发技巧l method in .h file and work with it in the cpp file? I have

my.h

#include <string>

public class me;
class me
{
public:
me();

private bool method(string name); //it is ok??

}

my.cpp

#include 'my.h';
me::me()
{
method(string name); //can i do this? isn't there another alternative?
}

method (String name)
{
cout<<"name"<<endl;
}

is not working.why?

I suggest you learn the basics of C++ from a tutorial

my.h

#include <string>

class me
{
    public:
       me();

       bool method(std::string name) const;
};

my.cpp

#include 'my.h';

me::me()
{
}

bool me::method(std::string name)
{
    std::cout << name << std::endl;
}

As written, there is no need for me::method to be a member function (it could be a static).

Numerous little fixes there. I get the sense that you are coming from C# (possibly java). Read up on the differences. Google has good sources :)

There are a number of issues with your code.

my.h

#include <string>

// public class me; // Absolutely not needed. From which language did you get this?

class me
{
public:
me();

private: // You need the colon here. 

bool method(string name); //it is ok?? // No. The class is called std::string. You should pass it by const-reference (const std::string& name);

}

my.cpp

#include 'my.h';
me::me()
{
// `name` is undefined here. You also don't need to specify the type.
//method(string name); //can i do this? isn't there another alternative? 
    method("earl");
}

// method (String name) // See previous comment about const-reference and the name of the class. Also note that C++ is case-sensitive. You also need to specify the return type and the class name:
bool me::method(const std::string& name)
{
    // cout<<"name"<<endl; // Close...
    std::cout << "My name is " << name << std::endl;
    return true; // we are returning a `bool, right?
}

You'll also need to call your code:

int main()
{
    me instance_of_me;
    return 0;
}

I suggest you take a look for a good C++ tutorial and some reading material.

Answers to questions in the comments:

could you please tell me why do I need to pass std::string through reference?

This question has already been asked (more than once) on StackOverflow. I recommend this answer.

And what is with me mo?

In hindsight mo was a terrible choice for a variable name. instance_of_me may have been a better choice. This line constructs an instance of me, calling the constructor (which in turn calls method("earl"))

You meant me method("hello"); in the main()

I certainly did not!

You declared method as a private member function. This method cannot, therefore, be called from outside the class.

First of all, you have missed : after private

Second, if method (String name) in the cpp file should be the method (String name) from your class, it must be:

bool me::method(std::string name)
{
    // ...
}

Third, if you want this bool me::method(std::string name) to be different function, a global one, not from you class, it must be:

ret_type method(std::string name)
{
    // ...
}

And, fourth,

cout<<"name"<<endl;

will pring the string (literal) "name". If you want to print the variable name, use it without the quotes:

std::cout<< name <<endl;

I'd recommend you to get a book

Ah, and this one:

me::me()
{
    method(string name); //can i do this? isn't there another alternative?
}

method(string name) - this is not valid syntax. It should be something like:

me::me()
{
    string name;
    // do something with name
    method( name ); // if "method" is a method, for real
}