jQuery: parse XML with inconsistent row data into a table

This is probably a very rookie question but i am stumped.

I have the following code which is parsing an XML file and putting each element into a table. My problem is that there is not always nine elements in each row and the names of each element changes between XML files. Is there any way to create a loop that runs through each row (without knowing the element name (col0, col1, etc) ) and puts it into a table?

The XML goes like this:

<row>
    <Col0>titles</Col0>
    <Col1>more titles</Col1>
    <Col2>title</Col2>
    <Col3>name</Col3>
    <Col4>another name</Col4>
    <Col5>different name</Col5>
    <Col6></Col6>
    <Col7></Col7>
    <Col8></Col8>
</row>
<row>
    <Col0>5:58</Col0>
    <Col1>-</Col1>
    <Col2>6:08</Col2>
    <Col3>6:11</Col3>
    &开发者_运维百科lt;Col4>6:15</Col4>
    <Col5>6:19</Col5>
    <Col6></Col6>
    <Col7></Col7>
    <Col8></Col8>
</row>

etc....

Here is my code:

<script type="text/javascript">
    $(document).ready(function()
  {
    $.get('newlayout.xml', function(d){
    $('.tabl').append('<table>');

    $(d).find('row').each(function(){

        var $row = $(this);

        var col01 = $row.find('Col0').text();
        var col02 = $row.find('Col1').text();
        var col03 = $row.find('Col2').text();
        var col04 = $row.find('Col3').text();
        var col05 = $row.find('Col4').text();
        var col06 = $row.find('Col5').text();
        var col07 = $row.find('Col6').text();
        var col08 = $row.find('Col7').text();
        var col09 = $row.find('Col8').text();


        html = '<tr>'  
        html += '<td style="width:80px"> ' + col01 + '</td>';
        html += '<td style="width:80px"> ' + col02 + '</td>' ;
        html += '<td style="width:80px"> ' + col03 + '</td>' ;
        html += '<td style="width:80px"> ' + col04 + '</td>' ;
        html += '<td style="width:80px"> ' + col05 + '</td>' ;
        html += '<td style="width:80px"> ' + col06 + '</td>' ;
        html += '<td style="width:80px"> ' + col07 + '</td>' ;
        html += '<td style="width:80px"> ' + col08 + '</td>' ;
        html += '<td style="width:80px"> ' + col09 + '</td>' ;
                    html += '</tr>';

        $('.tabl').append($(html));

    });
});
});

Thanks in advance,

Tom

try the following:

$('row').each(function(){
    var $row = $(this);
    $('.tabl').append($('<tr></tr>').append($row.children().wrapInner('<td style="width:80px"></td>').find('td')));
})

Working example at jsFiddle.

I think you can follow what's happening here. If not, ask away. It's mostly an issue of understanding the different jQuery functions, and for this nothing beats api.jquery.com

edit: This version gets rid of the empty cells, by selecting only those cells that are a parent of something (i.e. not empty):

$('row').each(function(){
    var $row = $(this);
    $('.tabl').append($('<tr></tr>').append($row.children().wrapInner('<td style="width:80px"></td>').find('td:parent')));
})

$(d).find('row').each(function() {
    var $row = $(this);
    html = '<tr>';
    var i = 0;

    while (true) {
        if ($.trim((colX = $row.find('Col' + i).text())) !== '') {
            html += '<td style="width:80px"> ' + colX + '</td>';
            i++;
        }
        else {
            break;
        }
    }

    html += '</tr>';
    $('.tabl').append($(html));
});

If you want to only have columns for fields with a name in the first row, then this will work for you:

http://jsfiddle.net/entropo/ffyDT/

$('row').each(function() {
    var $row = $(this),
        fieldcount = fieldcount || 0,
        afterfirst;
    if (! afterfirst) {
        fieldcount = $row.find(':not(:empty)').length;
        afterfirst = 1;
    }

    $('.tabl').append($('<tr />').append($row.children(':lt('+fieldcount+')')
        .wrapInner('<td />').find('td')));
});