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MVC3 - Reference to inherited property fails

I have a class PricingModel with two derived classes: Recurring and Packaged. in my home controller I make the following reference:

View开发者_StackOverflowBag.X = db.PricingModels.Where(x => x.Type == "Packaged").Select(x => x).ToArray(); foreach (var o in ViewBag.X) { var xy = o.Discount; }

which works fine. If I change that to:

var X = db.PricingModels.Where(x => x.Type == "Packaged").Select(x => x).ToArray(); foreach (var o in X) { var xy = o.Discount; }

the reference to o.Discount complains:

Error 2 'Website.Models.PricingModel' does not contain a definition for 'Discount' and no extension method 'Discount' accepting a first argument of type 'Website.Models.PricingModel' could be found (are you missing a using directive or an assembly reference?) C:\Users\ekkis\Documents\Visual Studio 2010\Projects\SkillScore\Website\Controllers\HomeController.cs 46 32 Website

I think that the ViewBag.X[0].Discount works because the ViewBag is untyped... the value's there but the compiler doesn't know about it. My question is: why can't doesn't the compiler see the property of the derived class?

I tried casting it but to no avail:

...ToArray().Cast<Packaged>()

also:

var xy = ((Packaged) o).Discount;

so what am I missing?


I think it would be better to use the OfType extension method instead of Cast.

db.PricingModels.OfType<Packaged>.ToList()

Cast does exactly that - cast, however ofType will actually only return items of type Pacakged. Also, the Select() is not needed as you're trasnforming an object of T to itself.

If I understand your code correctly, it might crash when a type is not a Packaged type.

And yes, the reason it works with the ViewBag is because the ViewBag is a Dynamic, so there is no compile-time checking as everything happens at runtime.


.Cast() won't work for non native types. so I've ended up doing:

List<PricingModel> Packages = db.PricingModels
   .Where(x => x.Type == "Packaged")
   .ToList();
foreach (Packaged o in Packages) { ... }

which works just fine (finally!)

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