Haskell Map function implementation issues

I just began to learn Haskell and am having trouble with adjusting to the language, for example on the implementation of map more specifically when trying to do similar operations as in the example bellow;

rotate :: Dimensions ->  imgBlock -> [(imgBlock,Int)]
rotate d ((p, pix), s, t) 
  = zip [((p, f pix), s, t) | f <- transformate (fst d)] [0..7]

makeAllRotations :: Dimensions -> [imgBlock] -> [(imgBlock,Int)]
makeAllRotations d ib = map concat (rotate d ib)              //Error points Here

Where

type imgBlock = (Block, Int, Int)
type Block = (Pnt, Pxl)
type Dimensions = (Int, Int)

And this is one of the errors i get

asdf.hs:73:30:
    Couldn't match expected type `(imgBlock, Int)'
                with actual type `[a0]'
    Expected type: [[a0]] -> (imgBlock, Int)
      Actual type: [开发者_如何学Go[a0]] -> [a0]
    In the first argument of `map', namely `concat'
    In the expression: map concat (rotate d ib)

I find myself quite frustrated trying to adjust to this new programming 'paradigm' where most of the things I managed to do are through trial and error. I am obviously not understanding map correctly, although i have read the documentation on this website, but all the examples are shown in console like map (2+) [1,2,3] not so much when using them in functions.

Could I get some pointers on where am i going wrong on my map implementation. Thks

The best way to find the problem is to look at the types:

rotate :: Dimensions -> ImgBlock -> [(ImgBlock,Int)]
makeAllRotations :: Dimensions -> [ImgBlock] -> [(ImgBlock,Int)]
map :: (a -> b) -> [a] -> [b]
concat :: [[a]] -> [a]

The map function is trying to call concat on each of the (ImgBlock,Int) pairs in the list returned by rotate. But concat expects to get a nested list as its argument. But the big thing that helped me figure out how to fix it was looking at rotate d ib. The second argument to rotate is ImgBlock, but in that context ib :: [ImgBlock]. You can't pass in a list when a single item is expected. But that's what the map function is for. It allows you to take a function that accepts a single item ('a' in the type signature above) and use that function when you have [a]. I suspect what you want is something like this:

makeAllRotations d ib = concat $ map (rotate d) ib

Because rotate returns a list, map (rotate d) ib returns a list of lists, which fits perfectly as the first argument to the concat function.