How to add an integer to an array?
This must be quite basic, but I was wondering how to add an integer to an array?
I know I can add strings like this:
NSMutableArray *trArray = [[NSMutableArray alloc] init];
[trArray addObject:@"0"];
[trArray addObject:@"1"开发者_StackOverflow];
[trArray addObject:@"2"];
[trArray addObject:@"3"];
But I guess I can't simply add integers like so:
NSMutableArray *trArray = [[NSMutableArray alloc] init];
[trArray addObject:0];
[trArray addObject:1];
[trArray addObject:2];
[trArray addObject:3];
At least the compiler isn't happy with that and tells me that I'm doing a cast without having told it so.
Any explanations would be very much appreciated.
Yes that's right. The compiler won't accept your code like this. The difference is the following:
If you write @"a String"
, it's the same as if you created a string and autoreleased it. So you create an object by using @"a String"
.
But an array can only store objects (more precise: pointers to object). So you have to create objects which store your integer.
NSNumber *anumber = [NSNumber numberWithInteger:4];
[yourArray addObject:anumber];
To retrive the integer again, do it like this
NSNumber anumber = [yourArray objectAtIndex:6];
int yourInteger = [anumber intValue];
I hope my answer helps you to understand why it doesn't work. You can't cast an integer to a pointer. And that is the warning you get from Xcode.
EDIT:
It is now also possible to write the following
[yourArray addObject:@3];
which is a shortcut to create a NSNumber. The same syntax is available for arrays
@[@1, @2];
will give you an NSArray containing 2 NSNumber objects with the values 1 and 2.
You have to use NSNumbers I think, try adding these objects to your array: [NSNumber numberWithInteger:myInt];
NSMutableArray *trArray = [[NSMutableArray alloc] init];
NSNumber *yourNumber = [[NSNumber alloc] numberWithInt:5];
[trArray addObject: yourNumber];
You can also use this if you want to use strings:
NSMutableArray *array = [[NSMutableArray alloc] init];
[array addObject:[NSString stringWithFormat:@"%d",1]];
[[array objectAtIndex:0] intValue];
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