In the below xml code, i need to get "b1" and "b2" as my output using xslt
In the below xml code, I need to get "b1" and "b2" as my output using xsl开发者_运维问答t.
<xml>
<a>
<b>
<b1>b1value</b1>
<b2>b2value</b2>
</b>
<b>
<b1>b1value2</b1>
<b2> 2value2</b2>
</b>
</a>
</xml>
I wrote the following XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="xml/a/b/*[b1='b1value']">
<xsl:value-of select="local-name()"/>
<br> </br>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
But it doesn't give me any output.. why?
Instead if i write
<xsl:for-each select="xml/a/b/*">
<xsl:value-of select="local-name()"/>
the output is:
b1
b2
b1
b2
the output i need is:
b1
b2
It's not clear exactly what you're trying to get for output.
However the reason you're not getting any output from your XSLT is that in your for-each, your xpath is looking for any children of <b> that also have a child <b> that contains "b1value".
You need to move your predicate:
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="xml/a/b[b1='b1value']/*">
<xsl:value-of select="local-name()"/>
<br> </br>
</xsl:for-each>
</body>
</html>
</xsl:template>
Do you mean this:
<xsl:for-each select="xml/a/b/*[text()='b1value']">
加载中,请稍侯......
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