overriding the jquery.param function
I have a problem with the jQuery.param function. jQuery uses + instead of %20 to URL-encode spaces
var obje = {
'test': 'tester 2'
}
console.log($.param(obje));
returns "test开发者_如何学C=tester+2"
so I thought about overriding this core function:
(function($){
$.fn.param = function( a, traditional ) {
console.log('custom $.param');
var s = [],
add = function( key, value ) {
// If value is a function, invoke it and return its value
value = jQuery.isFunction( value ) ? value() : value;
s[ s.length ] = encodeURIComponent( key ) + "=" + encodeURIComponent( value );
};
// Set traditional to true for jQuery <= 1.3.2 behavior.
if ( traditional === undefined ) {
traditional = jQuery.ajaxSettings.traditional;
}
// If an array was passed in, assume that it is an array of form elements.
if ( jQuery.isArray( a ) || ( a.jquery && !jQuery.isPlainObject( a ) ) ) {
// Serialize the form elements
jQuery.each( a, function() {
add( this.name, this.value );
} );
} else {
// If traditional, encode the "old" way (the way 1.3.2 or older
// did it), otherwise encode params recursively.
for ( var prefix in a ) {
buildParams( prefix, a[ prefix ], traditional, add );
}
}
return s.join("&");
// Return the resulting serialization
//return s.join( "&" ).replace( r20, "+" );
};
})(jQuery);
var obje = {
'test': 'tester 2'
}
console.log($.param(obje));
This fails however.. The $.param isn't overridden.
Any idea what can be wrong?
Thanks!
Edit: my solution (because I'm a new user I appearently may not answer my own question in 8 hours (Why is that?))
With the solution of ThiefMaster I still had the problem that buildParams is undefined. I solved this by calling the old function and then replacing the + back to %20
// modification of the jQuery.param function: spaces are encoded by jQuery.param with + instead of %20. replace these back to %20
(function($, oldFunction){
$.param = function( a, traditional ) {
var s = oldFunction.apply(oldFunction,[a,traditional]);
// Return the resulting serialization
return s.replace( '+', '%20' );
};
})(jQuery,jQuery.param);
You need to use $.param
instead of $.fn.param
(which would be a function to call on a jQuery object, e.g. $(...).param()
).
Old post I know, but for the sake of recorded knowledge. To replace the '+' left behind when using $.param(), consider doing the following:
(Using the code you provided)
var obje = {
'test': 'tester 2'
}
console.log($.param(obje).replace(/\+/g, "%20"));
That will result in: test = tester 2
Hope this helps someone.
The "re-replace" fix may also be implemented by using "beforeSend" in the ajax settings object:
{ beforeSend: function (request, settings) { settings.data = settings.data.replace(/\+/g, "%20"); } }
This approach is suitable for cases where you don't actually want to alter $.param()'s original behavior (for example, if you want "+" in URLs but "%20" for POST data).
[Edited because I remembered that string.replace() will only match once unless it's a regex object with the g flag.]
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