Django will this view shown in the admin index

Will this view shown as a link in admin index in a portion called modules? Which user can click on the link like normal admin class to view the view?

I have a class in called ListAdmin in Admin.py:

class ListAdmin(admin.ModelAdmin):
    def list_view(self, request):
        return question_list(request)

    def get_urls(self):
        urls = super(ListAdmin, self).get_urls()
        list_urls = patterns('', r'^list/$', self.list_view())

        return list_urls + urls

The view is in view.py

def question_list(request):
    #questions = Question.objects.filter(topic__icontains = 1)
    questions = Question.objects.all()
    return render_to_response('admin/question_list.html', {'questions':questions})
question_list = staff开发者_开发知识库_member_required(question_list)

The problem is I don't know how to register the ListAdmin into the admin, because it does not have a list model, and the Question model is already registered.

admin.site.register(???, ListAdmin)

The possible solution is this:

Multiple ModelAdmins/views for same model in Django admin

I added this into my admin.py, it succesfully added a link into the admin index:

class List(Question):
    class Meta:
        proxy = True

class ListAdmin(QuestionAdmin):
    def list_view(self, request):
        return question_list(request)

admin.site.register(List, ListAdmin)

I still think that it is wrong because if I take the line below out from the url.py, it will direct to the Question model:

url(r'^admin/modules/list/$', 'exam.admin.modules.views.question_list'),