converting a char* to BSTR* which contains special characters
I'm trying to convert a char*
to a BSTR*
, and my char*
has special characters in it from being encrypted. I have tried several approaches found on the web, but back in the calling vb code, I always end up with something different. I'm pretty sure this has to do with the special characters, because if I don't have them in, it seems to be ok....
my code is something along these lines...
_export myFunction(BSTR *VBtextin, BSTR *VBpassword, BSTR *VBtextout, FPINT encrypt) {
BSTR password开发者_如何学编程 = SysAllocString (*VBpassword);
char* myChar;
myChar = (char*) password //is this ok to cast? it seems to remain the same when i print out.
//then I encrypt the myChar in some function...and want to convert back to BSTR
//i've tried a few ways like below, and some other ways i've seen online...to no avail.
_bstr_t temp(myChar);
SysReAllocString(VBtextout, myChar);
any help would be greatly greatly appreciated!!!
Thanks!!!!
If you're manipulating the buffer, you probably don't want manipulate the char *
directly. First make a copy:
_export myFunction(BSTR *VBtextin, BSTR *VBpassword, BSTR *VBtextout, FPINT encrypt) {
UINT length = SysStringLen(*VBpassword) + 1;
char* my_char = new char[length];
HRESULT hr = StringCchCopy(my_char, length, *VBpassword);
If that all succeeds, perform your transformation. Make sure to handle failure as well, as appropriate for you.
if (SUCCEEDED(hr)) {
// Perform transformations...
}
Then make a copy back:
*VBtextout = SysAllocString(my_char);
delete [] my_char;
}
Also, have a read of Eric's Complete Guide to BSTR Semantics.
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