(php) if condition not working

I am going crazy here. The following simple if-condition does not produce the right output.

$xxx = 1;
if($xxx == 1)
    define('DEBUG', true);
else
    define('DEBUG', false);
var_dump($xxx)开发者_JAVA技巧;
var_dump(DEBUG);
die();

Output:

int(1)
bool(false)

I see absolutely no reason why the DEBUG constant is not being set to true. PHP's type juggling should allow this if-statement. And even if I put an intval in front of the variable, it still produces false as output.

Edit 2: I copied the exact code from above into a new file and it produces the expected output. So I don't know what is going on...

var_dump($vbulletin->userinfo['userid']);

Output :

string(1)

Your string length is one, and it seems to be empty (a space ?).

$vbulletin  = new stdClass();
$vbulletin->userinfo    = array('userid' =>  1);

if(1 == $vbulletin->userinfo['userid'])
    define('DEBUG', true);
else
    define('DEBUG', false);
var_dump(DEBUG);
echo "\n";
var_dump($vbulletin->userinfo['userid']);

There isn't anything wrong with your code. Running the above code gives me

bool(true) int(1) 

I suspect your $vbulletin->userinfo['userid'] variable has a different value to what you think it has

EDIT

When I change it to

$vbulletin->userinfo    = array('userid' =>  '1');

I get string(1) "1". You're string appears to be empty, and that's the reason it's failing.