LINQ to SQL query to determine if value starts with numeric
I have a project where I query users by first letter:
repository.GetAll().Where(q => q.BrukerIdent.StartsWith(letter.ToString())).ToList();
..where repository.GetAll()
returns an IQueryable<Bruker>
, BrukerIdent
is a string that contains the username, and letter
is a char-value coming in. This works perfectly, except that I also want to get users that starts with digits. And I don't want to sort by separate digits.
My mind yells for a StartsWith("\d")
but as far as I have found out it doesn't work this way. I have also thought of doing a 10-way OR clause, b开发者_运维知识库ut that would look like spaghetti, and I'm not sure of the efficiency.
Is there any "right" way to do it like this?
If this is for LINQ-to-SQL you could use SqlMethods.Like
method here:
var result = repository
.GetAll()
.Where(q => SqlMethods.Like(q.BrukerIdent, "[0-9]%"))
.ToList();
repository.GetAll().Where(q => Char.IsNumber(q.BrukerIdent[0]))
MSDN
var numbers = Enumerable
.Range(0, 10)
.Select(i => i.ToString(CultureInfo.InvariantCulture));
// var numbers = new[] { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 );
// var numbers = HashSet<int> { ... };
var q = from b in repository.GetAll()
where numbers.Contains(b.BrukerIdent.FirstOrDefault())) //[0]
select b;
I suspect @abatishchev's revised answer will help here, but if you are doing this lots, or this is an important query, then I strongly suggest a refactor. For example:
create table Test (
id int not null identity(1,1) primary key clustered,
name nvarchar(20) not null,
firstChar as (case when LEN(name) = 0 then null
else SUBSTRING(name,1,1) end) persisted
)
go
create nonclustered index Test_firstChar on Test (firstChar)
I can now do a very efficient first-character match simply by testing firstChar
. Which could be an integer instead if the numeric ones are particularly important.
Perhaps not so readable, but the following would probably work:
q.BrukerIdent >= "0" && q.BrukerIdent < ":"
Maybe there are some exotic collation sequences where this would fail, but I expect it would work in most situations.
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