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Return children using LINQ to XML

Using the following XML.

<?xml version="1.0"?>
<Message>
      <ArrayOfStock xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
            <Stock>
                  <StockID>9cddb639-25ee-4415-be07-3109e5ae9883</StockID>
                  <Description>Stock Item 0</Description>
            </Stock>
            <Stock>
                  <StockID>f89f02f9-b359-48c8-8d2f-3a950837f4fb</StockID>
                  <Description>Stock Item 1</Description>
            </Stock>
            <Stock>
                  <StockID>3338ec80-f59e-4979-a04c-f7d52e386bb7</StockID>
               开发者_Python百科   <Description>Stock Item 2</Description>
            </Stock>
      </ArrayOfStock>
</Message>

Could someone please show me how I would return just the ArrayOfStock XML?

I have used

using (MemoryStream memStream = new MemoryStream(this.Message))
{
    XDocument doc = XDocument.Load(memStream);
    var message = from arrayOfStock in doc.Elements("Message")
                  select arrayOfStock;
}     

And it seems to return the ArrayOfStock but also includes the message node itself.


Use this:

var arrayOfStockNodes = from arrayOfStock 
                        in doc.Root.Elements("ArrayOfStock") 
                        select arrayOfStock;

Because you want to have the ArrayOfStock tag, you should specify it...


I believe the answer to this question might help you.


If there can be more than one:

IEnumerable<XElement> arraysOfStock = doc.Root.Elements("ArrayOfStock");

If there can be only one:

XElement arrayOfStock = doc.Root.Element("ArrayOfStock");


doc.Descendants("ArrayOfStock").Concat(new[] { doc.Root });


try this

 var result = from c in XDocument.Load("PATH_OF_XML_FILE").Descendants("ArrayOfStock")
                          select c;
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