How do I add a Foreign Key Field to a ModelForm in Django?

What I would like to do is to display a single form that lets the user:

• Enter a document title (from Document model)
• Select one of their user_defined_code choices from a drop down list (populated by the UserDefinedCode model)
• Type in a unique_code (stored in the Code model)

I'm not sure how to go about displaying the fields for the foreign key relationships in a form. I know in a view you can use document.code_set (for example) to access the related objects for the current document object, but I'm not sure how to apply this to a ModelForm.

My model:

class UserDefinedCode(models.Model):
    name = models.CharField(max_length=8)
    owner = models.ForeignKey(User)

class Code(models.Model):
    user_defined_code = models.ForeignKey(UserDefinedCode)
    unique_code = models.CharField(max_length=15)

class Document(models.Model):
    title = models.CharField(blank=True, null=True, max_length=200)
    code = models.开发者_运维知识库ForeignKey(Code)
    active = models.BooleanField(default=True)

My ModelForm

class DocumentForm(ModelForm):
    class Meta:
        model = Document

In regards to displaying a foreign key field in a form you can use the forms.ModelChoiceField and pass it a queryset.

so, forms.py:

class DocumentForm(forms.ModelForm):
    class Meta:
        model = Document

    def __init__(self, *args, **kwargs):
        user = kwargs.pop('user','')
        super(DocumentForm, self).__init__(*args, **kwargs)
        self.fields['user_defined_code']=forms.ModelChoiceField(queryset=UserDefinedCode.objects.filter(owner=user))

views.py:

def someview(request):
    if request.method=='post':
        form=DocumentForm(request.POST, user=request.user)
        if form.is_valid():
            selected_user_defined_code = form.cleaned_data.get('user_defined_code')
            #do stuff here
    else:
        form=DocumentForm(user=request.user)

    context = { 'form':form, }

    return render_to_response('sometemplate.html', context, 
        context_instance=RequestContext(request))

from your question:

I know in a view you can use document.code_set (for example) to access the related objects for the current document object, but I'm not sure how to apply this to a ModelForm.

Actually, your Document objects wouldn't have a .code_set since the FK relationship is defined in your documents model. It is defining a many to one relationship to Code, which means there can be many Document objects per Code object, not the other way around. Your Code objects would have a .document_set. What you can do from the document object is access which Code it is related to using document.code.

edit: I think this will do what you are looking for. (untested)

forms.py:

class DocumentForm(forms.ModelForm):
    class Meta:
        model = Document
        exclude = ('code',)

    def __init__(self, *args, **kwargs):
        user = kwargs.pop('user','')
        super(DocumentForm, self).__init__(*args, **kwargs)
        self.fields['user_defined_code']=forms.ModelChoiceField(queryset=UserDefinedCode.objects.filter(owner=user))
        self.fields['unique_code']=forms.CharField(max_length=15)

views.py:

def someview(request):
    if request.method=='post':
        form=DocumentForm(request.POST, user=request.user)
        if form.is_valid():
            uniquecode = form.cleaned_data.get('unique_code')
            user_defined_code = form.cleaned_data.get('user_defined_code')
            doc_code = Code(user_defined_code=user_defined_code, code=uniquecode)
            doc_code.save()
            doc = form.save(commit=False)
            doc.code = doc_code
            doc.save()
            return HttpResponse('success')
    else:
        form=DocumentForm(user=request.user)

    context = { 'form':form, }

    return render_to_response('sometemplate.html', context, 
        context_instance=RequestContext(request))

actually you probably want to use get_or_create when creating your Code object instead of this.

doc_code = Code(user_defined_code=user_defined_code, code=uniquecode)