Evaluating a math expression in a Bash script

echo开发者_开发知识库 “Enter the value of variable x” 
read x 
echo “Enter the value of variable y” 
read y
answer="\( $x + $y \) \* \( $x + $y \) \* \( $x + $y \)  = $(( $x + $y ) * ($x + $y) * ($x + $y))"

I want a program to find (x+y)^3 and please let me know what should be the actual code

There is no need to use bc, you can use Bash builtin arithmetics instead:

echo $((($x+$y)**3))

It can be done simply using bc as:

$(echo "$(($x+$y))^3" | bc)

or simply using bash (thanks to lecodesportif):

$((($x+$y)**3))

You're missing a few parens.

Fixed:

answer="\( $x + $y \) \* \( $x + $y \) \* \( $x + $y \)  = $(( ($x + $y ) * ($x + $y) * ($x + $y) ))"

I hope this helps.

P.S. as you appear to be a new user, if you get an answer that helps you please remember to mark it as accepted, and/or give it a + (or -) as a useful answer.

You could also use:

let ANSWER=(x+y)**3