32 bit binary to ASCII 8086 assembly

I need to convert 32-bit number to ASCII. I don't know how I can do it ....

This is the code what I wrote : The biggest number that could convert is 0001FFFF , if I set Dx to 000F and Ax to FFFF the assembler will give me a divide overflow error !!!

data segment  
    save db 10 d开发者_开发技巧up(' ') , '$' ; the ASCII will save here
data ends

stack segment
    dw   128  dup(0)
stack ends

code segment
    assume cs:code , ds:data , ss:stack

    main proc far
    mov ax, data
    mov ds, ax
    mov es, ax



    mov di,offset save
    add di , 9

    mov ax,0ffffh
    mov dx,0001h


    mov cx,10  ; dx ax will divide by cx

    convert:
       div cx

       add dl,'0'
       mov [di],dl
       dec di

       mov dx,0



       cmp ax,cx
    jge convert

    add al,'0'
    mov [di] , al

    ;show the number
    mov ah,09h
    mov dx,offset save
    int 21h





    ; wait for any key....    
    mov ah, 1
    int 21h

    mov ax, 4c00h ; exit to operating system.
    int 21h    
    main endp
code ends    

end main

what should i do?

thanks in advance

Hehe that's an easy one :P

I believe you might be getting a 'Divide Error' but not specifically a 'Devide by ZERO error'

You say that you get an error when DX=0xF right?

Well 0x000FFFFF = 1048575 ... divide this by 10 you get >65535 ... The answer: you simply get a divide overflow. The result needs to fit within AX.

I'd say you'd put out a CR (015), an LF (012) and take the exit to BIOS.

Who'da thunk we'd ever see int 21 again?