Haskell string to list [duplicate]

This question already has answers here: Closed 11 years ago.

Possible Duplicate:

convert string list to int list in haskell

I have a string 12345. How can I show it in list fo开发者_如何学JAVArm like [1,2,3,4,5]? And also what if i have a string like ##%%? I can't convert it to Int. How can view it in the form [#,#,%,%]?

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import Data.Char (digitToInt)

map digitToInt "12345"

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Use intersperse

myShow :: String -> String
myShow s = concat ["[", intersperse ',' s, "]"]

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You should map the function read x::Int to each of the elements of the string as a list of chars:

map (\x -> read [x]::Int) "1234"

If you have non-digit characters you should filter it first like this:

import Data.Char
map (\x -> read [x]::Int) (filter (\x -> isDigit x) "1234##56")

That results in:

[1,2,3,4,5,6]

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Have you taken a look at this answer? Convert string list to int list

A String is just a list of characters in Haskell after all. :)

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Try using splitEvery with length 1