2 Floating divs, Need the first one to auto-size according to parent div and 2nd floating div

This is how my code may go:-

<div id="parent" style="width:49%">
  <div id="left" style="float:left;clear:both;width:auto">BLAH!BLAH!Content goes here</div>
  <div id="right" style="float:left;clear:both:width:250px">Content again goes here!</div>
</div>

So basically I want left to auto-size based on the 开发者_如何学JAVAthe width of "right" but must stay in limits of the "parent" container!

I looked up many places but didn't find sensible answers! Hope this website can help me! :D

Thanks in advance

Float #right to the right, and do not float #left but give it a margin-right which is equal to the width of #right. If you float #left, it will take up the size of its contents, but if you don't float it, it will take up the possible maximum width it can. And you just lower this maximum width by setting a margin.

Demo

Notice that in the markup I changed the order of divs:

  <div id="right">Content again goes here!</div>
  <div id="left">BLAH!BLAH!Content goes here</div>

And the important part of the CSS:

#parent { 
    width: /*whatever you need*/; 
    overflow: hidden; /* to let it take up the height of floated elements */
}

#left {
    margin-right: 250px;
}

#right {
    float: right;
    width: 250px;
}

Tested in FF4, Chrome, IE8.

You need to use JavaScript to detect remaining space. This cannot be done with CSS alone. With jQuery you can do

var parentw = $('#parent').width();
var rightw = $('#right').width();
$('#left').width(parentw - rightw);

Check working example http://jsfiddle.net/NP4vb/

Pure CSS Answer:

<div id="parent" style="width:49%">
  <div id="left" style="float:left;clear:both;width:calc(100% - 250px)">BLAH!BLAH!Content goes here</div>
  <div id="right" style="float:left;clear:both:width:250px">Content again goes here!</div>
</div>