Pygtk: Remove a widget from a container and reuse it later
I'm using a custom container where I need to reorder widgets but there are no methods to do it. So I tried to remove all the widgets and add them again in order.
开发者_Python百科The problem is that this is not working well, I can't see the widgets after adding them again, I guess what's happening is that when I remove the widgets they become unrealized.
Is there any way of removing a widget an reuse it later?
The pygtk docs provide a bit of insight.
Note that the container will own a reference to widget, and that this may be the last reference held; so removing a widget from its container can cause that widget to be destroyed. If you want to use widget again, you should add a reference to it.
EDITS
I just quickly modified pygtk's Hello World to add/remove/reorder widgets in a container. This works because the button1 is a member variable of the class, it never goes out of scope.
#!/usr/bin/env python
# example helloworld2.py
import pygtk
pygtk.require('2.0')
import gtk
class HelloWorld2:
# Our new improved callback. The data passed to this method
# is printed to stdout.
def callback_remove(self, widget, data):
self.box1.remove(self.button1);
def callback_add(self, widget, data):
self.box1.pack_start(self.button1, True, True, 0)
# another callback
def delete_event(self, widget, event, data=None):
gtk.main_quit()
return False
def __init__(self):
# Create a new window
self.window = gtk.Window(gtk.WINDOW_TOPLEVEL)
# This is a new call, which just sets the title of our
# new window to "Hello Buttons!"
self.window.set_title("Hello Buttons!")
# Here we just set a handler for delete_event that immediately
# exits GTK.
self.window.connect("delete_event", self.delete_event)
# Sets the border width of the window.
self.window.set_border_width(10)
# We create a box to pack widgets into. This is described in detail
# in the "packing" section. The box is not really visible, it
# is just used as a tool to arrange widgets.
self.box1 = gtk.HBox(False, 0)
# Put the box into the main window.
self.window.add(self.box1)
# Creates a new button with the label "Button 1".
self.button1 = gtk.Button("Button 1")
# Now when the button is clicked, we call the "callback" method
# with a pointer to "button 1" as its argument
self.button1.connect("clicked", self.callback_remove, "button 1")
# Instead of add(), we pack this button into the invisible
# box, which has been packed into the window.
self.box1.pack_start(self.button1, True, True, 0)
# Always remember this step, this tells GTK that our preparation for
# this button is complete, and it can now be displayed.
self.button1.show()
# Do these same steps again to create a second button
self.button2 = gtk.Button("Button 2")
# Call the same callback method with a different argument,
# passing a pointer to "button 2" instead.
self.button2.connect("clicked", self.callback_add, "button 2")
self.box1.pack_start(self.button2, True, True, 0)
# The order in which we show the buttons is not really important, but I
# recommend showing the window last, so it all pops up at once.
self.button2.show()
self.box1.show()
self.window.show()
def main():
gtk.main()
if __name__ == "__main__":
hello = HelloWorld2()
main()
Just set the widget's visibility property to False, and set it to True later, with the set_visible
method.
no he need only widgrt.its objects not need.then visible must not used.it will only hide graphicaly.but memmory still not released
remove function is the answer
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