What happens if memory leaks on rootfs?
I have a linux totally on rootfs ( which as I understand is an instance of ramfs ). There's no hard disk and no swap. And I got a process that leaks memory continuously. The virutal memory eventually grows to 4 times the size of physical memory, shown with top. I can't understand what's happening. rootfs is supposed to take RAM only, right ? If I have no disk to swap to, how开发者_如何学C does the Virtual Memory grows to 4 times the physical memory ?
Not all allocated memory has to be backed by a block device; the glibc-people consider this behavior a bug:
BUGS
By default, Linux follows an optimistic memory allocation
strategy. This means that when malloc() returns non-NULL
there is no guarantee that the memory really is available.
This is a really bad bug. In case it turns out that the
system is out of memory, one or more processes will be killed
by the infamous OOM killer. In case Linux is employed under
circumstances where it would be less desirable to suddenly
lose some randomly picked processes, and moreover the kernel
version is sufficiently recent, one can switch off this
overcommitting behavior using a command like:
# echo 2 > /proc/sys/vm/overcommit_memory
See also the kernel Documentation directory, files
vm/overcommit-accounting and sysctl/vm.txt.
精彩评论