AJAX response that i can't understand
I have 2 questions :
If i send the ajax request to self page (from abc.php to abc.php) like this :
$.ajax({
type: "POST",
url: "some.php",
data: "name=John&location=Boston",
success: function(msg){
alert( "Data Saved: " + msg );
}
});
What will msg variable contain if I have a full webpage (with div's , forms, imgs) ? Will it contain the whole html code source ? How to tell ajax to return only specific details (like for example a php $variable after querying a database for a record based on Name and Location) . Remember some.php is the same file that contains the ajax script.
I want to make a .php script that contains all querys posible to manage a database like this:
if(isset($_GET['option']) && $_GET['option'] == 'insert') { code here .. and echo div`s .. etc) }
if(isset($_GET['option']) && $_GET['option'] == 'del') { code here .. and echo div`s .. etc) }
if(isset($_GET['option']) && $_GET['option'] == 'update') { code here .. and echo div`s .. etc) }
if(isset($_GET['option']) && $_GET['option'] == 'find') { code here .. and echo div`s .. etc) }
if(isset($_GET['option']) && $_GET['option'] == 'abc') { code here .. and echo div`s .. etc) }
and i want to run ajax request based on option and retrive specific results (like php $variables ... and so on)
How do i do that ?
Anyway the most important question is how to i get ajax.result that contain开发者_如何学C just a php $variable or an $array if the page that receive ajax request already contains <html><body><divs><tables><h4><h3>.... etc ?
Because jquery.ajax() has a documentation quite complex/complicated on it's options like accepts, async, complete, contentType, context .. and so on.
?
Thanks a lot.
You can use the dataType option to specify the type of data that you are expecting back from the server. In your case JSON might be a good option since the php page can return a String in the form:
{name:value}
that that is easy to process as a JSON object on the client.
e.g. Found on this page
$.ajax({
url: url,
dataType: 'json',
data: data,
success: callback
});
Your callback function will then process the JSON and retrieve the value. As you can see from the link, you can use the getJSON() method as a shortcut.
The response variable msg will contain the full html of the page you have requested. To get a php variable instead, you need to pack up the variable in a way that javascript can understand, which usually means serializing the object / variable in a json format and then using $.parseJSON or eval on msg to turn the resultant string into a javascript object / array.
The answer is, don't make an ajax request to a page that already contains <html><body etc, use a page without that stuff.
All you need is
echo $variable;
加载中,请稍侯......
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