Why doesn't this compile?

When I try to declare iss using the first form, g++ gives me "error: no match for 'operator>>' in 'iss >> s'". But don't the two different declarations do the same thing?

#include <iostream>
#include <sstream>
#include <string>


int main() {
    const char *buf = "hello world";
    std::string ss(buf);
    //std::istringstream iss(std::string(buf)); // this doesn't work
    std::istringstream iss(ss); // 开发者_如何学Cbut this does
    std::string s;
    iss >> s;
}

This is known as the "most vexing parse" of C++: what looks like an instance declaration to you actually looks like a function declaration to the compiler.

std::string name(); //function declaration
std::string name;  //object declaration with default constructor

std::stringstream ss(std::string(buf));  //function declaration
std::stringstream ss(std::string buf);  //another function declaration
std::stringstream ss(std::string);  //also a function declaration
std::stringstream ss(std::string());  //ditto, argument names are optional

std::stringstream ss((std::string(buf))); //object declaration

Note the extra brackets in the last example. These brackets wouldn't be legal in a function declaration.

The first example with the default constructor is well-known. What adds unclarity in the second case is that brackets around parameter names in C++ are legal but optional. For example, you can define a function like this:

void foo(int (bar))
{}

Basically you'll run into this every time when all arguments to a constructor are temporaries from constructor invocations that take 0 or 1 arguments, and the quick solution is to put extra brackets around one of the arguments.

It's because istringstream takes a const reference to a string. So you can't just write this:

std::istringstream iss(std::string(buf));

Well, actually you can, but it means you are declaring a function iss, which takes a std::string and returns std::istringstream. Equivalently, you could write:

std::istringstream iss(std::string buf);

It's pretty sick C++ stuff.

I guess there is some confusion about the type returned by std::string(char*) because this:

  std::istringstream iss((std::string)std::string(buf));

works.

The first argument to construct an istream from a string needs to be: const string & str which this does not create:

    std::string(buf)

While the following code illustrates the point, it leaks memory, so don't actually use it.

    std::istringstream iss(*new std::string(buf));

Don't you need to use namespace std;?