Rails - return an array of months for a select tag
I'm in an app that is on Rails 2.3.8, and need to return an array of month names and numbers to be plugged into an options_for_select statement. What I've got so far is kind of working, but not really. The reason I'm doing things this way is because the select statement needs a prompt, which you can't give options_for_select by default in 2.3.8 (at least to my knowledge).
Here is what I have so far:
@months = [['-', '']]
(1..12).each {|m| @months << [[Date::MONTHNAMES[m], m]]}
So what I'm looking to get returned are options like this:
<option value="1">January</option>
<option value="2">February</option>
However, instead I get:
<option value="January1">January1</option>
<option value="February2">February2</option>
开发者_开发技巧
What am I missing?
Try this!
@months = [['-', '']]
(1..12).each {|m| @months << [Date::MONTHNAMES[m], m]}
Date::MONTHNAMES.each_with_index.collect{|m, i| [m, i]}
=> [[nil, 0],
["January", 1],
["February", 2],
["March", 3],
["April", 4],
["May", 5],
["June", 6],
["July", 7],
["August", 8],
["September", 9],
["October", 10],
["November", 11],
["December", 12]]
Abbreviated selection with default option
Date::ABBR_MONTHNAMES.compact.each_with_index.collect{|m, i| [m, i+1]}
.insert(0, ['Please Select', nil])
=> [["Please Select", nil],
["Jan", 1],
["Feb", 2],
["Mar", 3],
["Apr", 4],
["May", 5],
["Jun", 6],
["Jul", 7],
["Aug", 8],
["Sep", 9],
["Oct", 10],
["Nov", 11],
["Dec", 12]]
You can use rails helper select_month, like:
select_month(Date.today)
This is my solution for you, in case you work with I18n-based projects, that requires multilingual features:
def month_array
# Gets the first day of the year
date = Date.today.beginning_of_year
# Initialize the months array
months = {}
# Iterate through the 12 months of the year to get it's collect
12.times do |i| # from 0 to 11
# Get month name from current month number in a selected language (locale parameter)
month_name = I18n.l(date + i.months, format: '%B', locale: :en).capitalize
months[month_name] = i + 1
end
return months
end
# => {"January"=>1, "February"=>2, "March"=>3, "April"=>4, "May"=>5, "June"=>6, "July"=>7, "August"=>8, "September"=>9, "October"=>10, "November"=>11, "December"=>12}
Regards
Here's a sexy way to get the months only if that's all you want:
Date::MONTHNAMES.slice(1..-1).map(&:to_sym)
Working for ROR 4
select_month(0 , prompt: 'Choose month')
If you want it to be translated to the selected language.
t("date.month_names")
Found this nifty way to shift off the first nil
but return a new collection of months. You cannot use shift on it since that would try to modify the frozen variable.
Date::MONTHNAMES.drop(1)
Try it
<% (1..12).each do |month|%>
<%= link_to t('date.month_names')[month], '#' %>
<% end %>
# alternative 1
Date::MONTHNAMES.compact.zip(1.upto(12)).to_h
# alternative 2
Date::MONTHNAMES.compact.zip([*1..12]).to_h
Outputs:
{"January"=>0, "February"=>1, "March"=>2, "April"=>3, "May"=>4, "June"=>5, "July"=>6, "August"=>7, "September"=>8, "October"=>9, "November"=>10, "December"=>11}
Example:
# using simple_form
f.input :month, collection: Date::MONTHNAMES.compact.zip(1.upto(12)).to_h
精彩评论