Get Application Directory

Does someone k开发者_开发知识库now how do I get the path of my application directory? (e.g. /data/data/my.app.lication/)

Currently I'm using this method: myActivity.getFilesDir().getParent(); but it seems to me like a workaround when there's a simpler solution. Also, the side-effect is the creation of the files directory, which is un-needed.

Clarification: First - Thanks for the repliers. I try to understand if there's already exists method that does it, not for another work-around.

There is a simpler way to get the application data directory with min API 4+. From any Context (e.g. Activity, Application):

getApplicationInfo().dataDir

http://developer.android.com/reference/android/content/Context.html#getApplicationInfo()

PackageManager m = getPackageManager();
String s = getPackageName();
PackageInfo p = m.getPackageInfo(s, 0);
s = p.applicationInfo.dataDir;

If eclipse worries about an uncaught NameNotFoundException, you can use:

PackageManager m = getPackageManager();
String s = getPackageName();
try {
    PackageInfo p = m.getPackageInfo(s, 0);
    s = p.applicationInfo.dataDir;
} catch (PackageManager.NameNotFoundException e) {
    Log.w("yourtag", "Error Package name not found ", e);
}

Just use this in your code

 context.getApplicationInfo().dataDir

I got this

String appPath = App.getApp().getApplicationContext().getFilesDir().getAbsolutePath();

from here:

For current Android application package:

public String getDataDir(Context context) throws Exception {
    return context.getPackageManager().getPackageInfo(context.getPackageName(), 0).applicationInfo.dataDir;
}

For any package:

public String getAnyDataDir(Context context, String packageName) throws Exception {
    return context.getPackageManager().getPackageInfo(packageName, 0).applicationInfo.dataDir;
}

If you're trying to get access to a file, try the openFileOutput() and openFileInput() methods as described here. They automatically open input/output streams to the specified file in internal memory. This allows you to bypass the directory and File objects altogether which is a pretty clean solution.

Based on @jared-burrows' solution. For any package, but passing Context as parameter...

public static String getDataDir(Context context) throws Exception {
    return context.getPackageManager()
            .getPackageInfo(context.getPackageName(), 0)
            .applicationInfo.dataDir;
}